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In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

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प्रश्न

In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

योग
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उत्तर

Let the parts of red pigment required to mix with 1800 mL of base be x.

The given information, in the form of a table, is as follows:

Parts of red pigment 1 x
Parts of base (in mL) 75 1800

The parts of red pigment and the parts of the base are in direct proportion.

Therefore, we obtain

`1/75 = x/1800`

=> x = `(1 xx 1800)/75`

=> x = 24

Thus, 24 parts of red pigments should be mixed with 1800 mL of base.

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अध्याय 11: Direct and Inverse Proportions - EXERCISE 11.1 [पृष्ठ १३६]

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एनसीईआरटी Mathematics [English] Class 8
अध्याय 11 Direct and Inverse Proportions
EXERCISE 11.1 | Q 3. | पृष्ठ १३६

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