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Question
In a parallelogram ABCD, ∠D = 135°, determine the measure of ∠A and ∠B.
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Solution
\[\text{ In a parallelogram, opposite angles have the same value }. \]
\[ \therefore \angle D = \angle B\]
\[ = 135°\]
\[\text{ Also }, \angle A + \angle B + \angle C + \angle D = 360°\]
\[\angle A + \angle D = 180° \left( \text{ Popposite angles have the same value }\right)\]
\[\angle A = 180°- 135° = 45°\]
\[\angle A = 45°\]
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