Advertisements
Advertisements
Question
In the given figure, compute the value of x.

Advertisements
Solution
In the given figure,∠DCB = 45, ∠CBA = 45 and ∠BAD = 35
Here, we will produce AD to meet BC at E

Now, using angle sum property of the triangle
In ΔAEB
∠BAE +∠AEB + ∠EBA = 180°
∠AED + 35°+ 45° = 180°
∠AEB + 80° = 180°
∠AEB = 180° - 80°
∠AEB = 100°
Further, BEC is a straight line. So, using the property, “the angles forming a linear pair are supplementary”, we get,
∠AEB + ∠AEC = 180°
100 + ∠AEC = 180°
∠AEC = 180°- 100°
∠AEC = 80°
Also, using the property, “an exterior angle of a triangle is equal to the sum of its two opposite interior angles”
In ΔDEC, x is its exterior angle
Thus,
∠X = ∠DCE + ∠DEC
= 50° + 80°
= 130°
Therefore, X = 130°.
APPEARS IN
RELATED QUESTIONS
Compute the value of x in the following figure:

In a Δ ABC, the internal bisectors of ∠B and ∠C meet at P and the external bisectors of ∠B and ∠C meet at Q, Prove that ∠BPC + ∠BQC = 180°.
In ΔRST (See figure), what is the value of x?

In the given figure, show that: ∠a = ∠b + ∠c

(i) If ∠b = 60° and ∠c = 50° ; find ∠a.
(ii) If ∠a = 100° and ∠b = 55° : find ∠c.
(iii) If ∠a = 108° and ∠c = 48° ; find ∠b.
Can a triangle together have the following angles?
33°, 74° and 73°
Find, giving a reason, the unknown marked angles, in a triangle drawn below:

Classify the following triangle according to sides:

The length of the sides of the triangle is given. Say what types of triangles they are 3 cm, 4 cm, 5 cm.
Q is a point on the side SR of a ∆PSR such that PQ = PR. Prove that PS > PQ.
In the following figure, PQ ⊥ RQ, PQ = 5 cm and QR = 5 cm. Then ∆PQR is ______.

