Advertisements
Advertisements
Question
Find the unknown marked angles in the given figure:
Advertisements
Solution
In the figure,
∠A + ∠B + ∠C = 180° .....(Sum of angles of a triangle)
x° + 90° + x° = 180°
⇒ 2x°+ 90° = 180°
⇒ 2x° = 180° − 90°
⇒ 2x°= 90°
⇒ x° = `(90° )/2=45° `
Hence ∠A = x° = 45°
and ∠C = x° = 45°
APPEARS IN
RELATED QUESTIONS
The angles of a triangle are (x − 40)°, (x − 20)° and `(1/2x-10)^@.` find the value of x
AB is a line segment. P and Q are points on opposite sides of AB such that each of them is equidistant from the points A and B (See Fig. 10.26). Show that the line PQ is perpendicular bisector of AB.
Is the following statement true and false :
A triangle can have two right angles.
Is the following statement true and false :
A triangle can have two obtuse angles.
Is the following statement true and false :
An exterior angle of a triangle is less than either of its interior opposite angles.
In a triangle, an exterior angle at a vertex is 95° and its one of the interior opposite angle is 55°, then the measure of the other interior angle is
If the sides of a triangle are produced in order, then the sum of the three exterior angles so formed is
The correct statement out of the following is 
In the given figure, AB is parallel to CD. Then the value of b is
Bisectors of the angles B and C of an isosceles triangle with AB = AC intersect each other at O. BO is produced to a point M. Prove that ∠MOC = ∠ABC.
