Advertisements
Advertisements
Question
Find the unknown marked angles in the given figure:
Advertisements
Solution
In the figure,
∠A + ∠B + ∠C = 180° .....(Sum of angles of a triangle)
b° + 50° + b° = 180°
⇒ 2b° + 50° = 180°
⇒ 2b° = 180° − 50° = 130°
⇒ b° = `(130°)/2=65°`
Hence ∠A = b° = 65°
and ∠C = b° = 65°
APPEARS IN
RELATED QUESTIONS
In a ΔABC, ∠ABC = ∠ACB and the bisectors of ∠ABC and ∠ACB intersect at O such that ∠BOC = 120°. Show that ∠A = ∠B = ∠C = 60°.
Can a triangle have two acute angles?Justify your answer in case.
Is the following statement true and false :
A triangle can have at most one obtuse angles.
Is the following statement true and false :
An exterior angle of a triangle is greater than the opposite interior angles.
In the given figure, side BC of ΔABC is produced to point D such that bisectors of ∠ABC and ∠ACD meet at a point E. If ∠BAC = 68°, find ∠BEC.
State, if the triangle is possible with the following angles :
20°, 70°, and 90°
Calculate the unknown marked angles of the following figure :
Find, giving a reason, the unknown marked angles, in a triangle drawn below:
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
15 cm, 20 cm, 25 cm
If an angle of a triangle is equal to the sum of the other two angles, find the type of the triangle
