Advertisements
Advertisements
Question
If two acute angles of a right triangle are equal, then each acute is equal to
Options
30°
45°
60°
90°
Advertisements
Solution
In the given problem, we have a right angled triangle and the other two angles are equal.

So, In ΔABC
∠A = 90°
∠B = ∠C
Now, using the angle sum property of the triangle, in ΔABC, we get,
∠A + ∠B + ∠C = 180°
90° + 2∠B = 180° (∠B = ∠C)
2∠B= 180° - 90°
`∠B = (90°)/2`
∠B = 45°
APPEARS IN
RELATED QUESTIONS
Two angles of a triangle are equal and the third angle is greater than each of those angles
by 30°. Determine all the angles of the triangle.
Compute the value of x in the following figure:

In the given figure, if AB || CD, EF || BC, ∠BAC = 65° and ∠DHF = 35°, find ∠AGH.

The bisects of exterior angle at B and C of ΔABC meet at O. If ∠A = x°, then ∠BOC =
State, if the triangle is possible with the following angles :
125°, 40°, and 15°
In the following, find the marked unknown angle:

Find x, if the angles of a triangle is:
x°, 2x°, 2x°
Q is a point on the side SR of a ∆PSR such that PQ = PR. Prove that PS > PQ.
In the following figure, points lying in the interior of the triangle PQR are ______, that in the exterior are ______ and that on the triangle itself are ______.

Which two triangles have ∠B in common?
