Advertisements
Advertisements
Question
Find the unknown marked angles in the given figure:

Advertisements
Solution
In the figure,
∠A + ∠B + ∠C = 180° .....(Sum of angles of a triangle)
k°+ k°+ k°= 180°
⇒ 3k° = 180°
⇒ k° =`(180°)/3=60°`
Hence ∠A = k° = 60°, ∠B = k° = 60°
and ∠C = k° = 60°
APPEARS IN
RELATED QUESTIONS
Can a triangle have two right angles? Justify your answer in case.
Can a triangle have All angles equal to 60°? Justify your answer in case.
In the given figure, compute the value of x.

In Δ ABC, BD⊥ AC and CE ⊥ AB. If BD and CE intersect at O, prove that ∠BOC = 180° − A.
In the given figure, AE bisects ∠CAD and ∠B= ∠C. Prove that AE || BC.

In the following, find the marked unknown angle:

Classify the following triangle according to angle:

The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
8.4 cm, 16.4 cm, 4.9 cm
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
15 cm, 20 cm, 25 cm
The exterior angle of a triangle is equal to the sum of two
