Advertisements
Advertisements
Question
Find the unknown marked angles in the given figure:
Advertisements
Solution
In the figure,
∠A + ∠B + ∠C = 180° .....(Sum of angles of a triangle)
k°+ k°+ k°= 180°
⇒ 3k° = 180°
⇒ k° =`(180°)/3=60°`
Hence ∠A = k° = 60°, ∠B = k° = 60°
and ∠C = k° = 60°
APPEARS IN
RELATED QUESTIONS
In a ΔABC, if ∠A = 55°, ∠B = 40°, find ∠C.
The bisectors of base angles of a triangle cannot enclose a right angle in any case.
In a ΔABC, ∠ABC = ∠ACB and the bisectors of ∠ABC and ∠ACB intersect at O such that ∠BOC = 120°. Show that ∠A = ∠B = ∠C = 60°.
Is the following statement true and false :
All the angles of a triangle can be greater than 60°.
In Δ ABC, BD⊥ AC and CE ⊥ AB. If BD and CE intersect at O, prove that ∠BOC = 180° − A.
Side BC of a triangle ABC has been produced to a point D such that ∠ACD = 120°. If ∠B = \[\frac{1}{2}\]∠A is equal to
Calculate the unknown marked angles of the following figure :
In ∆ABC, C = 56° C = 56° ∠B = ∠C and ∠A = 100° ; find ∠B.
Classify the following triangle according to angle:
The number of angles in the following figure is ______.
