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Question
In the following verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:-
y = ex + 1 y'' − y' = 0
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Solution
We have,
y'' − y' = 0 ............(1)
Now,
y = ex +1
⇒ y'= ex
⇒ y'' = ex
Putting the above values in (1), we get
LHS = ex − ex = 0 = RHS
Thus, y = ex + 1 is the solution of the given differential equation.
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