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Dy + (X + 1) (Y + 1) Dx = 0 - Mathematics

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Question

dy + (x + 1) (y + 1) dx = 0

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Solution

We have,
\[dy + \left( x + 1 \right)\left( y + 1 \right) dx = 0\]
\[ \Rightarrow dy = - \left( x + 1 \right)\left( y + 1 \right) dx\]
\[ \Rightarrow \frac{1}{y + 1}dy = - \left( x + 1 \right) dx\]
Integrating both sides, we get
\[\int\frac{1}{y + 1}dy = - \int\left( x + 1 \right) dx\]
\[ \Rightarrow \log \left| y + 1 \right| = - \frac{x^2}{2} - x + C\]
\[ \Rightarrow \log \left| y + 1 \right| + \frac{x^2}{2} + x = C\]
\[\text{ Hence, }\log \left| y + 1 \right| + \frac{x^2}{2} + x =\text{ C is the required solution . }\]

 

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Chapter 22: Differential Equations - Exercise 22.07 [Page 55]

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RD Sharma Mathematics [English] Class 12
Chapter 22 Differential Equations
Exercise 22.07 | Q 32 | Page 55

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