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Question
Solve the following differential equation `("d"y)/("d"x)` = x2y + y
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Solution
`("d"y)/("d"x)` = x2y + y
∴ `("d"y)/("d"x)` = y(x2 + 1)
∴ `("d"y)/y` = (x2 + 1) dx
Integrating on both sides, we get
`int ("d"y)/y = int(x^2 + 1) "d"x`
∴ log |y| = `x^3/3 + x + "c"`
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