मराठी

In the Following Verify that the Given Functions (Explicit Or Implicit) is a Solution of the Corresponding Differential Equation:- Y = Ex + 1 Y'' − Y' = 0 - Mathematics

Advertisements
Advertisements

प्रश्न

In the following verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:-

y = ex + 1            y'' − y' = 0

बेरीज
Advertisements

उत्तर

We have,

y'' − y' = 0 ............(1)

Now,

y = ex +1

⇒ y'= ex

⇒ y'' = ex

Putting the above values in (1), we get

LHS = ex − ex = 0 = RHS

Thus, y = ex + 1 is the solution of the given differential equation.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 22: Differential Equations - Revision Exercise [पृष्ठ १४४]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 22 Differential Equations
Revision Exercise | Q 3.1 | पृष्ठ १४४

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

\[x^2 \left( \frac{d^2 y}{d x^2} \right)^3 + y \left( \frac{dy}{dx} \right)^4 + y^4 = 0\]

Show that Ax2 + By2 = 1 is a solution of the differential equation x \[\left\{ y\frac{d^2 y}{d x^2} + \left( \frac{dy}{dx} \right)^2 \right\} = y\frac{dy}{dx}\]

 


Show that y = ex (A cos x + B sin x) is the solution of the differential equation \[\frac{d^2 y}{d x^2} - 2\frac{dy}{dx} + 2y = 0\]


For the following differential equation verify that the accompanying function is a solution:

Differential equation Function
\[x\frac{dy}{dx} = y\]
y = ax

For the following differential equation verify that the accompanying function is a solution:

Differential equation Function
\[x\frac{dy}{dx} + y = y^2\]
\[y = \frac{a}{x + a}\]

Differential equation \[\frac{dy}{dx} = y, y\left( 0 \right) = 1\]
Function y = ex


Differential equation \[\frac{d^2 y}{d x^2} - \frac{dy}{dx} = 0, y \left( 0 \right) = 2, y'\left( 0 \right) = 1\]

Function y = ex + 1


Differential equation \[\frac{d^2 y}{d x^2} - 3\frac{dy}{dx} + 2y = 0, y \left( 0 \right) = 1, y' \left( 0 \right) = 3\] Function y = ex + e2x


\[\frac{dy}{dx} = x e^x - \frac{5}{2} + \cos^2 x\]

xy (y + 1) dy = (x2 + 1) dx


\[x\frac{dy}{dx} + \cot y = 0\]

\[\frac{dy}{dx} = \frac{x\left( 2 \log x + 1 \right)}{\sin y + y \cos y}\]

tan y dx + sec2 y tan x dy = 0


\[\left( x - 1 \right)\frac{dy}{dx} = 2 x^3 y\]

Solve the following differential equation: 
(xy2 + 2x) dx + (x2 y + 2y) dy = 0


Solve the following differential equation:
\[y\left( 1 - x^2 \right)\frac{dy}{dx} = x\left( 1 + y^2 \right)\]

 


\[\frac{dy}{dx} = 2xy, y\left( 0 \right) = 1\]

Find the particular solution of the differential equation \[\frac{dy}{dx} = - 4x y^2\]  given that y = 1, when x = 0.


\[\left( x + y \right)^2 \frac{dy}{dx} = 1\]

\[\left( x + y + 1 \right)\frac{dy}{dx} = 1\]

2xy dx + (x2 + 2y2) dy = 0


Solve the following differential equations:
\[\frac{dy}{dx} = \frac{y}{x}\left\{ \log y - \log x + 1 \right\}\]


The surface area of a balloon being inflated, changes at a rate proportional to time t. If initially its radius is 1 unit and after 3 seconds it is 2 units, find the radius after time t.


Experiments show that radium disintegrates at a rate proportional to the amount of radium present at the moment. Its half-life is 1590 years. What percentage will disappear in one year?


Write the differential equation obtained eliminating the arbitrary constant C in the equation xy = C2.


The differential equation satisfied by ax2 + by2 = 1 is


Which of the following is the integrating factor of (x log x) \[\frac{dy}{dx} + y\] = 2 log x?


The integrating factor of the differential equation \[x\frac{dy}{dx} - y = 2 x^2\]


Choose the correct option from the given alternatives:

The solution of `1/"x" * "dy"/"dx" = tan^-1 "x"` is


Solve the following differential equation.

`dy/dx = x^2 y + y`


Solve the following differential equation.

`dy/dx + y` = 3


Solve the following differential equation.

`(x + a) dy/dx = – y + a`


Solve the differential equation:

`e^(dy/dx) = x`


Solve:

(x + y) dy = a2 dx


Solve the differential equation (x2 – yx2)dy + (y2 + xy2)dx = 0


Solve the following differential equation

`y log y ("d"x)/("d"y) + x` = log y


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×