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In the Following Verify that the Given Functions (Explicit Or Implicit) is a Solution of the Corresponding Differential Equation:- Y = Ex + 1 Y'' − Y' = 0

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प्रश्न

In the following verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:-

y = ex + 1            y'' − y' = 0

योग
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उत्तर

We have,

y'' − y' = 0 ............(1)

Now,

y = ex +1

⇒ y'= ex

⇒ y'' = ex

Putting the above values in (1), we get

LHS = ex − ex = 0 = RHS

Thus, y = ex + 1 is the solution of the given differential equation.

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अध्याय 21: Differential Equations - Revision Exercise [पृष्ठ १४४]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 21 Differential Equations
Revision Exercise | Q 3.1 | पृष्ठ १४४

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