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Cos Y D Y D X = E X , Y ( 0 ) = π 2

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प्रश्न

\[\cos y\frac{dy}{dx} = e^x , y\left( 0 \right) = \frac{\pi}{2}\]
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उत्तर

\[\cos y\frac{dy}{dx} = e^x , y\left( 0 \right) = \frac{\pi}{2}\]
\[ \Rightarrow \cos y\ dy = e^x dx\]
Integrating both sides, we get
\[\int\cos y\ dy = \int e^x dx\]
\[ \Rightarrow \sin y = e^x + C . . . . . (1)\]
\[\text{ We know that at }x = 0, y = \frac{\pi}{2} . \]
Substituting the values of x and y in (1), we get
\[1 = 1 + C\]
\[ \Rightarrow C = 0\]
Substituting the value of C in (1), we get
\[\sin y = e^x \]
\[ \Rightarrow y = \sin^{- 1} \left( e^x \right)\]
\[\text{ Hence, }y = \sin^{- 1} \left( e^x \right)\text{ is the required solution }.\]

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अध्याय 21: Differential Equations - Exercise 22.07 [पृष्ठ ५६]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 21 Differential Equations
Exercise 22.07 | Q 45.4 | पृष्ठ ५६

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