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Solve the differential equation dydxdydx+2xy = y

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प्रश्न

Solve the differential equation `"dy"/"dx" + 2xy` = y

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उत्तर

Given equation is `"dy"/"dx" + 2xy` = y.

⇒ `"dy"/"dx"` = y – xy

⇒ `"dy"/"dx"` = y(1 –2x)

⇒ `"dy"/y` = (1 –2x)dx

Integrating both sides, we have

`int "dy"/"dx" = int (1 - 2x)"d"x`

⇒ log y = x – x2 + log c

⇒ log y – log c = x – x2

⇒ `log  y/"c"` = x – x2

⇒ `y/"c" = "e"^(x - x^2)`

∴ y = `"c" . "e"^(x - x^2)` 

Hence, the required solution is y = `"c" . "e"^(x - x^2)` .

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अध्याय 9: Differential Equations - Exercise [पृष्ठ १९३]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 9 Differential Equations
Exercise | Q 5 | पृष्ठ १९३

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