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( X − 1 ) D Y D X = 2 X Y

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प्रश्न

\[\left( x - 1 \right)\frac{dy}{dx} = 2 xy\]
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उत्तर

We have,
\[\left( x - 1 \right)\frac{dy}{dx} = 2 xy\]
\[ \Rightarrow \left( x - 1 \right)dy = 2xy dx\]
\[ \Rightarrow \frac{2x}{\left( x - 1 \right)}dx = \frac{1}{y}dy\]
Integrating both sides, we get
\[2\int\frac{x}{\left( x - 1 \right)}dx = \int\frac{1}{y}dy\]
\[ \Rightarrow 2\int\frac{x - 1 + 1}{x - 1}dx = \int\frac{1}{y}dy\]
\[ \Rightarrow 2\int dx + 2\int\frac{1}{x - 1}dx = \int\frac{1}{y}dy\]
\[ \Rightarrow 2x + 2 \log\left| x - 1 \right| = \log\left| y \right| + C\]

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अध्याय 21: Differential Equations - Exercise 22.07 [पृष्ठ ५५]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 21 Differential Equations
Exercise 22.07 | Q 1 | पृष्ठ ५५

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