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For each of the following differential equations find the particular solution. (x − y2 x)dx − (y + x2 y) dy = 0, when x = 2, y = 0

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प्रश्न

For each of the following differential equations find the particular solution.

(x − y2 x) dx − (y + x2 y) dy = 0, when x = 2, y = 0

योग
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उत्तर

(x − y2 x)dx − (y + x2 y) dy = 0, when x = 2, y = 0

∴ x(1- y2) dx = y(1 + x2 ) dy

∴ `(xdx)/(1+x^2) = (ydy)/(1-y^2)`

Integrating on both sides, we get

`int( 2x)/(1+x^2) dx = int(2y)/(1-y^2 )dy`

∴ `int( 2x)/(1+x^2) dx = - int(-2y)/(1-y^2 )dy`

∴ `log | 1 + x^2| = -log| 1-y^2| + log |c|`

∴ `log |1 + x^2 | = log |c /(1-y^2)|`

∴  (1 + x 2) ( 1 - y2 ) = c  …(i)

When x = 2, y = 0, we have

(1 + 4) (1 - 0) = c

∴  c = 5

Substituting c = 5 in (i),we get

(1 + x2) ( 1-y2 ) = 5,

which is the required particular solution.

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अध्याय 8: Differential Equation and Applications - Exercise 8.3 [पृष्ठ १६५]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 8 Differential Equation and Applications
Exercise 8.3 | Q 2.1 | पृष्ठ १६५

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