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Question
Solve the following differential equation.
xdx + 2y dx = 0
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Solution
xdx + 2y dy = 0
Integrating on both sides, we get
`int x dx +2 int y dy = 0`
∴ `x^2/2 + (2y^2)/2 = c_1`
∴ x2 + 2y2 = c ...[2c1 = c]
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