A(△TRP) : A(△TPK) = 3 : 2
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Question
In the following figure RP : PK= 3 : 2, then find the value of A(ΔTRP) : A(ΔTPK).
Sum
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Solution
Ratio of the areas of two triangles with common or equal heights is equal to the ratio of their corresponding bases.
`(A(triangleTRP))/(A(triangleTPK))`
`="RP"/"PK"`
`=3/2`
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In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.
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Now, A(ΔPQB) = `1/2 xx square xx square`
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= `square/square`
