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Question
In ΔABC, the medians BE and CD are produced to the points P and Q respectively such that BE = EP and CD = DQ. Prove that: Q A and P are collinear.
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Solution
In ΔBDC and ΔADQ,
CD = DQ ....(given)
∠BDC = ∠ADQ ....(vertically opposite angles)
BD = AD ....(D is the mid-point of AB)
∴ ΔBDC ≅ ΔADQ
⇒ ∠DBC = ∠DAQ (c.p.c.t)....(i)
And, BC = AQ (c.p.c.t)....(ii)
Similarly, we can prove ΔCEB ≅ ΔAEP
⇒ ∠ECB = ∠EAP (c.p.c.t)....(iii)
And, BC = AP (c.p.c.t)....(iv)
In ΔABC,
∠ABC + ∠ACB ++ ∠BAC = 180°
⇒ ∠DBC + ∠ECB + ∠BAC = 180°
⇒ ∠DAQ + ∠EAP + ∠BAC = 180° ...[From (i) and (iii)]
⇒ Q, A, P are collinear.
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