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Triangle Abc is Right-angled at B. Given that Ab = 9 Cm, Ac = 15 Cm and D, E Are the Mid-points of the Sides Ab and Ac Respectively, Calculate (I) the Length of Bc (Ii) the Area of δAde.

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Question

In Fig. below, triangle ABC is right-angled at B. Given that AB = 9 cm, AC = 15 cm and D,
E are the mid-points of the sides AB and AC respectively, calculate
(i) The length of BC (ii) The area of ΔADE.

 

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Solution

 

In right  ΔABC, ∠B = 90°

By using Pythagoras theorem

            `AC^2  = AB^2+ BC^2`

⇒       `15^2 = 9^2 +BC^2`

⇒        BC =`sqrt(15^2 - 9^2)`

⇒       BC =`sqrt(225-81)`

⇒       BC =`sqrt144`

               = 12cm 

In ΔABC

D and E are midpoints of  AB and AC

∴ DE || BC, DE = `1/2` BC       [By midpoint theorem]

AD = OB = `(AB)/ 2= 9/2`  = 4 . 5cm          [ ∵ D is the midpoint of AB]

DE = `(BC)/2 = 12/2` = 6cm        

Area of ΔADE = `1/2 xxAD xx DE `

= `1/2× 4 .5 × 6 = 13.5cm^2`

 

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Chapter 13: Quadrilaterals - Exercise 13.4 [Page 63]

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R.D. Sharma Mathematics [English] Class 9
Chapter 13 Quadrilaterals
Exercise 13.4 | Q 7 | Page 63

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