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Question
In triangle ABC, AD is the median and DE, drawn parallel to side BA, meets AC at point E.
Show that BE is also a median.
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Solution
ln ΔABC,
AD is the median of BC.
⇒ D is the mid-point of BC.
Given at DE || BA
By the Converse of the Mid-point theorem,
⇒ DE bisects AC
⇒ E is the mid-point of AC
⇒ BE is the median of AC
that is BE is also a median.
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