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In Triangle Abc, Ad is the Median and De, Drawn Parallel to Side Ba, Meets Ac at Point E. Show that Be is Also a Median.

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प्रश्न

In triangle ABC, AD is the median and DE, drawn parallel to side BA, meets AC at point E.
Show that BE is also a median.

योग
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उत्तर


ln ΔABC,
AD is the median of BC.
⇒ D is the mid-point of BC.
Given at DE || BA
By the Converse of the Mid-point theorem,
⇒ DE bisects AC
⇒ E is the mid-point of AC
⇒ BE is the median of AC
that is BE is also a median.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Mid-point Theorem and Its Converse [Including Intercept Theorem] - Exercise 12 (A) [पृष्ठ १५१]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 11 Mid-point Theorem and Its Converse [Including Intercept Theorem]
Exercise 12 (A) | Q 15 | पृष्ठ १५१

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