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In Triangle Abc ; D and E Are Mid-points of the Sides Ab and Ac Respectively. Through E, a Straight Line is Drawn Parallel to Ab to Meet Bc at F. Prove that Bdef is a Parallelogram. If Ab = 16 Cm - Mathematics

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प्रश्न

In triangle ABC ; D and E are mid-points of the sides AB and AC respectively. Through E, a straight line is drawn parallel to AB to meet BC at F.
Prove that BDEF is a parallelogram. If AB = 16 cm, AC = 12 cm and BC = 18 cm,
find the perimeter of the parallelogram BDEF.

योग
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उत्तर

The figure is shown below

From figure since E is the midpoint of AC and EF || AB
Therefore F is the midpoint of BC and 2DE = BC or DE = BF
Again D and E are midpoints,
therefore DE || BF and EF = BD
Hence BDEF is a parallelogram.
Now,
BD = EF = `1/2"AB" = 1/2` x 16 = 8 cm

BF = DE = `1/2"BC" = 1/2` x 18 = 9 cm

Therefore perimeter of BDEF = 2( BF + EF ) = 2( 9 + 8 ) = 34 cm.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Mid-point and Its Converse [ Including Intercept Theorem] - Exercise 12 (B) [पृष्ठ १५४]

APPEARS IN

सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 12 Mid-point and Its Converse [ Including Intercept Theorem]
Exercise 12 (B) | Q 10 | पृष्ठ १५४

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