English

Let Abc Be an Isosceles Triangle in Which Ab = Ac. If D, E, F Be the Mid-points of the Sides Bc, Ca and a B Respectively, Show that the Segment Ad and Ef Bisect Each Other at Right Angles.

Advertisements
Advertisements

Question

Let Abc Be an Isosceles Triangle in Which Ab = Ac. If D, E, F Be the Mid-points of the Sides Bc, Ca and a B Respectively, Show that the Segment Ad and Ef Bisect Each Other at Right Angles.

Answer in Brief
Advertisements

Solution

Since  D, E and F are the midpoints of sides

BC, CA and AB respectively

∴ AB || DF and  AC || FD

AB || DF and AC || FD

ABDF is a parallelogram

AF = DE and AE = DF

`1/2`AB = DE and `1/2` AC = DF

DE = DF           ( ∵ AB = AC )

AE = AF = DE = DF                        

ABDF is a rhombus

⇒ AD and FE bisect each other at right angle.

shaalaa.com
  Is there an error in this question or solution?
Chapter 13: Quadrilaterals - Exercise 13.4 [Page 64]

APPEARS IN

R.D. Sharma Mathematics [English] Class 9
Chapter 13 Quadrilaterals
Exercise 13.4 | Q 11 | Page 64

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

In below fig. ABCD is a parallelogram and E is the mid-point of side B If DE and AB when produced meet at F, prove that AF = 2AB.


ABC is a triangle and through A, B, C lines are drawn parallel to BC, CA and AB respectively
intersecting at P, Q and R. Prove that the perimeter of ΔPQR is double the perimeter of
ΔABC


In triangle ABC, the medians BP and CQ are produced up to points M and N respectively such that BP = PM and CQ = QN. Prove that:

  1. M, A, and N are collinear.
  2. A is the mid-point of MN.

In the given figure, AD and CE are medians and DF // CE.
Prove that: FB = `1/4` AB.


In a parallelogram ABCD, M is the mid-point AC. X and Y are the points on AB and DC respectively such that AX = CY. Prove that:
(i) Triangle AXM is congruent to triangle CYM, and

(ii) XMY is a straight line.


ABCD is a parallelogram.E is the mid-point of CD and P is a point on AC such that PC = `(1)/(4)"AC"`. EP produced meets BC at F. Prove that: 2EF = BD.


In ΔABC, D, E and F are the midpoints of AB, BC and AC.
If AE and DF intersect at G, and M and N are the midpoints of GB and GC respectively, prove that DMNF is a parallelogram.


In the given figure, PS = 3RS. M is the midpoint of QR. If TR || MN || QP, then prove that:

RT = `(1)/(3)"PQ"`


In the given figure, T is the midpoint of QR. Side PR of ΔPQR is extended to S such that R divides PS in the ratio 2:1. TV and WR are drawn parallel to PQ. Prove that T divides SU in the ratio 2:1 and WR = `(1)/(4)"PQ"`.


The quadrilateral formed by joining the mid-points of the sides of a quadrilateral PQRS, taken in order, is a rhombus, if ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×