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In a Fort 150 Men Had Provisions for 45 Days. After 10 Days, 25 Men Left the Fort. How Long Would the Food Last at the Same Rate?

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Question

In a fort 150 men had provisions for 45 days. After 10 days, 25 men left the fort. How long would the food last at the same rate?

Sum
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Solution 1

After 10 days:

For 150 men, provision will last (45 − 10)

days = 35 days

⇒ For 1 man, the provisions will last

= 150 × 35 days

And for (150 − 25) = 125 men, the provisions

will last for =`(150xx35)/125`

= 42 days

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Solution 2

Given: 

  1. 150 men have food for 45 days.
  2. After 10 days, 25 men leave the fort.
  3. We need to find how long the remaining food will last for 125 men.

The total amount of food is:

Total food = 150⋅45 = 6750 man-days.

Food consumed by 150 men in 10 days is

Food consumed = 150⋅10 = 1500 man-days.

The remaining food after 10 days is

Remaining food = 6750 − 1500 = 5250 man-days.

After 25 men leave, the remaining men are:

Remaining men = 150 − 25 = 125.

The number of days the remaining food will last for 125 men is:

Remaining days = `"Remaining food"/"Remaining men"=5250/125`

= 42 days

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Time and Work
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Chapter 10: Direct and Inverse Variations - Exercise 10 (B) [Page 123]

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Selina Concise Mathematics [English] Class 8 ICSE
Chapter 10 Direct and Inverse Variations
Exercise 10 (B) | Q 5 | Page 123

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