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Question
In a conductor 6.25 × `10^16` electrons flow from its end A to B in 2 s. Find the current flowing through the conductor (e = 1.6 × `10^-19` C)
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Solution
Number of electrons flowing through the conductor,
N = `6.25 × 10^16` electrons
Time taken, t = 2 s
Given, e = `1.6 × 10^-19` C
Let I be the current flowing through the conductor.
Then, I = `"ne"/t`
∴ I = `((6.25 xx 10^16)(1.6 xx10^-19))/2`
= ` 5 xx 10^-3`A
Or, I = 5 mA
Thus, 5 mA current flows from B to A.
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