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Find the Vector and Cartesian Equations of a Line Passing Through (1, 2, –4) and Perpendicular to the Two Lines `(X - 8)By3 = (Y + 19)By(-16) = (Z - 10)By7` and `(X - 15)By3 = (Y - 29)By8 = (Z - 5)By(-5)`

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Question

Find the vector and Cartesian equations of a line passing through (1, 2, –4) and perpendicular to the two lines `(x - 8)/3 = (y + 19)/(-16) = (z - 10)/7` and `(x - 15)/3 = (y - 29)/8 = (z - 5)/(-5)`

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Solution

The given lines are

`(x - 8)/3 = (y + 19)/(-16) = (z - 10)/7`..............(1)

and `(x - 15)/3 = (y - 29)/8 = (z - 5)/(-5)`............(2)

Let abc be the direction ratios of the required line.

Since the required line is perpendicular to (1) and (2), we have

3a − 16b + 7c = 0 .....(3)

and 3a + 8b - 5c = 0.....(4)

Solving (3) and (4) by the method of cross multiplication, we have

`a/(80-56) = b/(21+15) = c/(24 + 48)`

`=>a/24 = b/36 = c/72`

`=> a/2 = b/3 = c/6`

Thus, the required line has the direction ratio 2, 3, 6.

Thus, the Cartesian equation of the required line is

`(x - 1)/2 =  (y - 2)/3 = (x + 4)/6`

Also, the vector equation of the required line is

`vecr = (hati + 2hatj - 4hatk) + lambda(2hati + 3hatj + 6hatk)`

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2016-2017 (March) Delhi Set 1

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