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Find the values of x for y=[x(x-2)]2 is an increasing function.

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Question

Find the values of x for  `y = [x(x - 2)]^2` is an increasing function.

Sum
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Solution

We know,  y = [x (x – 2)]² = x² (x + 4 – 4x)

= x4 – 4x3 + 4x2
On differentiating with respect to x,

`dy/dx` = 4x2 - 12x2 + 8x

= 4x (x2 - 3x + 2)

= 4x ( x - 1) (x - 2)

`dy/dx` = 0

`=>` 4x ( x - 1) (x - 2) = 0

`therefore` x = 0, 1, 2

∴ Four parts of real number line from x = 0, x = 1, x = 2 are intervals.

(`- infty`, 0), (0, 1), (1, 2), (2, 2) are formed.

Interval (∞, 0) (0, 1) (1, 2) (2, ∞)
Sign of x -ve +ve +ve +ve
sign of (x - 1) -ve - ve +ve +ve
sign of (x - 2) -ve - ve -ve +ve
sign of `dy/dx` -ve +ve -ve +ve
nature of function decreasing increasing decreasing increasing

∴ y is an increasing function in (0, 1) ∪ (2, ∞)

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Chapter 6: Application of Derivatives - Exercise 6.2 [Page 205]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 6 Application of Derivatives
Exercise 6.2 | Q 8 | Page 205

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