Advertisements
Advertisements
Question
Find the diagonal of a quadrilateral whose area is 756cm2 and the perpendicular from the opposite vertices are 17cm and 19cm.
Advertisements
Solution

In Quadrilateral ABCD, BD is a diagonal, AM ⊥ BD, Cl ⊥ BD
AM = 17cm and CL = 19cm and Ar(Quandrilateral ABCD) = 756cm2
Let diagonal BD = x cm
Ar(Quandrilateral ABCD)
= `(1)/(2) xx "BD"("Am" + "CL")`
⇒ 756 = `(1)/(2) xx (19 + 17)`
⇒ 756 = 18x
⇒ x = 42cm.
APPEARS IN
RELATED QUESTIONS
The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

The length of a rectangle is twice the side of a square and its width is 6 cm greater than the side of the square. If the area of the rectangle is three times the area of the square; find the dimensions of each.
The area of a rectangular is 640 m2. Taking its length as x cm; find in terms of x, the width of the rectangle. If the perimeter of the rectangle is 104 m; find its dimensions.
Calculate the area of quadrilateral ABCD, in which ∠ABD = 90°, triangle BCD is an equilateral triangle of side 24 cm and AD = 26 cm.
The width of a rectangular room is `4/7`of its length, x, and its perimeter is y. Write an equation connecting x and y. Find the length of the room when the perimeter is 4400 cm.
Find the area and the perimeter of a square with diagonal 24 cm. [Take √2 = 1.41 ]
Find the area of quadrilateral PQRS.

In the following, find the value of ‘a’ for which the given points are collinear
(2, 3), (4, a) and (6, – 3)
Find the area of the quadrilateral whose vertices are at (– 9, 0), (– 8, 6), (– 1, – 2) and (– 6, – 3)
Let P(11, 7), Q(13.5, 4) and R(9.5, 4) be the midpoints of the sides AB, BC and AC respectively of ∆ABC. Find the coordinates of the vertices A, B and C. Hence find the area of ∆ABC and compare this with area of ∆PQR.
