Advertisements
Advertisements
Question
The perimeter of a rectangular field is `3/5`km. If the length of the field is twice its width; find the area of the rectangle in sq. meters.
Advertisements
Solution
Let the width be x and length 2x km.
Hence
`2 ( x + 2x ) = 3/5`
x = `1/10`km
= 100 m
Hence the width is 100m and length is 200m
The required area is given by
A = length x width
= 100 x 200
= 20,000 sq .m
APPEARS IN
RELATED QUESTIONS
Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.
A wire when bent in the form of a square encloses an area = 576 cm2. Find the largest area enclosed by the same wire when bent to form;
(i) an equilateral triangle.
(ii) A rectangle whose adjacent sides differ by 4 cm.
The diagonals of a quadrilateral are 16 cm and 13 cm. If they intersect each other at right angles; find the area of the quadrilateral.
The length of a rectangle is twice the side of a square and its width is 6 cm greater than the side of the square. If the area of the rectangle is three times the area of the square; find the dimensions of each.
A footpath of uniform width runs all around the outside of a rectangular field 30 m long and 24 m wide. If the path occupies an area of 360 m2, find its width.
Two adjacent sides of a parallelogram are 24 cm and 18 cm. If the distance between the longer sides is 12 cm; find the distance between the shorter sides.
The diagram, given below, shows two paths drawn inside a rectangular field 80 m long and 45 m wide. The widths of the two paths are 8 m and 15 m as shown. Find the area of the shaded portion.
The perimeter of a semicircular plate is 108 cm. find its area.
The quadrilateral swimming pool shown is surrounded by concrete patio. Find the area of the patio
When proving that a quadrilateral is a trapezium, it is necessary to show
