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Question
The perimeter of a rectangular field is `3/5`km. If the length of the field is twice its width; find the area of the rectangle in sq. meters.
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Solution
Let the width be x and length 2x km.
Hence
`2 ( x + 2x ) = 3/5`
x = `1/10`km
= 100 m
Hence the width is 100m and length is 200m
The required area is given by
A = length x width
= 100 x 200
= 20,000 sq .m
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