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Question
Find the area of the quadrilateral whose vertices are at (– 9, 0), (– 8, 6), (– 1, – 2) and (– 6, – 3)
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Solution
Let the vertices A(– 9, 0), B(– 8, 6), C(– 1, –2) and D(– 6, – 3)
Plot the vertices in a graph and take them in counter-clockwise order.
Area of the Quadrilateral DCBA
= `1/2[(x_1y_2 + x_2y_3 + x_3y_4 + x_4y_1) - (x_2y_1 + x_3y_2 + x_4y_3 + x_1y_4)]`
= `1/2[33 + 35]`
= `1/2 xx 68`
= 34 sq.units
Area of the Quadrilateral = 34 sq.units
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