Advertisements
Advertisements
Question
The perimeter of a rectangular board is 70 cm. Taking its length as x cm, find its width in terms of x.
If the area of the rectangular board is 300 cm2; find its dimensions.
Advertisements
Solution
Let b be the breadth of the rectangle. then its perimeter
2(x + b) = 70
x + b = 35
b = 35 - x
Again
x × b = 300
x(35 - x) = 300
35x - x2 = 300
0 = x2 - 35x + 300
(x - 15) (x - 20) = 0
x = 15, 20
Hence, its length is 20 cm and width is 15 cm.
APPEARS IN
RELATED QUESTIONS
The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

The distance between parallel sides of a trapezium is 15 cm and the length of the line segment joining the mid-points of its non-parallel sides is 26 cm. Find the area of the trapezium.
Trapezium given below; find its area.

The perimeter of a rhombus is 46 cm. If the height of the rhombus is 8 cm; find its area.
A triangle and a parallelogram have the same base and the same area. If the side of the triangle is 26 cm, 28 cm, and 30 cm and the parallelogram stands on the base 28 cm, find the height of the parallelogram.
A quadrilateral field of unequal has a longer diagonal with 140m. The perpendiculars from opposite vertives upon this diagonal are 20m and 14m. Find the area of the field.
Vertices of given triangles are taken in order and their areas are provided aside. Find the value of ‘p’.
| Vertices | Area (sq.units) |
| (0, 0), (p, 8), (6, 2) | 20 |
Vertices of given triangles are taken in order and their areas are provided aside. Find the value of ‘p’.
| Vertices | Area (sq.units) |
| (p, p), (5, 6), (5, –2) | 32 |
The quadrilateral swimming pool shown is surrounded by concrete patio. Find the area of the patio
When proving that a quadrilateral is a trapezium, it is necessary to show
