Advertisements
Advertisements
Question
The floor of a room is of size 6 m x 5 m. Find the cost of covering the floor of the room with 50 cm wide carpet at the rate of Rs.24.50 per metre. Also, find the cost of carpeting the same hall if the carpet, 60 cm, wide, is at the rate of Rs.26 per metre.
Advertisements
Solution
Area of floor of a room
= 6m x 5m
= 30m2
Let the length of the carpet that is 50cm wide be l m.
∴ Area of carpet
= length x breadth
= l m x 50cm
= l x 0.5m2
Since area of carpet
= Area of floor of a room
⇒ l x 0.5 = 30
⇒ l `(30)/(0.5)`
= 60m
∴ Cost of carpet at Rs.24.50per mate
= Rs.60 x 24.50
= Rs.1470
Let the length of the carpet that is 60cm wide be L m.
∴ Area of carpet
= length x breadth
= l m x 60cm
= l x 0.6m2
Since area of carpet
= Area of floor of a room
⇒ l x 0.6 = 30
⇒ l `(30)/(0.6)`
= 50m
∴ Cost of carpet at Rs.26per mate
= Rs.50 x 26
= Rs.1300.
APPEARS IN
RELATED QUESTIONS
Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.
The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.
Trapezium given below; find its area.
The width of a rectangular room is `4/7`of its length, x, and its perimeter is y. Write an equation connecting x and y. Find the length of the room when the perimeter is 4400 cm.
The length of a rectangular verandah is 3 m more than its breadth. The numerical value of its area is equal to the numerical value of its perimeter.
(i) Taking x as the breadth of the verandah, write an equation in x that represents the above statement
(ii) Solve the equation obtained in (i) above and hence find the dimensions of the verandah.
The diagram, given below, shows two paths drawn inside a rectangular field 80 m long and 45 m wide. The widths of the two paths are 8 m and 15 m as shown. Find the area of the shaded portion.
Find the diagonal of a quadrilateral whose area is 756cm2 and the perpendicular from the opposite vertices are 17cm and 19cm.
Find the area of quadrilateral PQRS.
When proving that a quadrilateral is a parallelogram by using slopes you must find
If vertices of a quadrilateral are at A(– 5, 7), B(– 4, k), C(– 1, – 6) and D(4, 5) and its area is 72 sq. units. Find the value of k.
