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Question
A rectangular plot of land measures 45 m x 30 m. A boundary wall of height 2.4 m is built all around the plot at a distance of 1 m from the plot. Find the area of the inner surface of the boundary wall.
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Solution
Length of the wall = 45 + 2 = 47 m
Breath of the wall = 30 + 2 = 32 m
Hence area of the inner surface of the wall is given by
A = ( 47 x 2 x 2.4 ) + ( 32 x 2 x 2.4 )
= 225.6 + 153.6
= 379.2 m2
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