Question

A rectangular plot of land measures 45 m x 30 m. A boundary wall of height 2.4 m is built all around the plot at a distance of 1 m from the plot. Find the area of the inner surface of the boundary wall.

Answer 1

Length of the wall = 45 + 2 = 47 m

Breath of the wall = 30 + 2 = 32 m

Hence area of the inner surface of the wall is given by

A = ( 47 x 2 x 2.4 ) + ( 32 x 2 x 2.4 )
= 225.6 + 153.6
= 379.2 m²