Advertisements
Advertisements
प्रश्न
The quadrilateral swimming pool shown is surrounded by concrete patio. Find the area of the patio
Advertisements
उत्तर

Area of the Quadrilateral ABCD = `1/2[(x_1y_2 + x_2y_3 + x_3y_4 + x_4y_1) - (x_2y_1 + x_3y_2 + x_4y_3 + x_1y_4)]`
= `1/2[(16 + 80 + 36 + 80) - (-64 - 24 - 100 - 24)]`
= `1/2[212 - (-212)]`

= `1/2[212 + 212]`
= `1/2[424]`
= 212 sq. units
Area of the Quadrilatera swimming pool EFGH = `1/2[(6 + 42 + 12 + 30) - (- 30 - 6 - 42 - 12)]`
= `1/2[90 - (- 90)]`

= `1/2[90 + 90]`
= `1/2 xx 180`
= 90 sq. units
Area of the patio = Area of the Quadrilateral ABCD – Area of the Quadrilateral EFGH
= (212 – 90) sq. units
Area of the patio = 122 sq. units
APPEARS IN
संबंधित प्रश्न
Trapezium given below; find its area.
Trapezium given below; find its area.
A rectangular plot 85 m long and 60 m broad is to be covered with grass leaving 5 m all around. Find the area to be laid with grass.
A wire when bent in the form of a square encloses an area of 484 m2. Find the largest area enclosed by the same wire when bent to from:
- An equilateral triangle.
- A rectangle of length 16 m.
The figure given below shows the cross-section of a concrete structure. Calculate the area of cross-section if AB = 1.8 cm, CD = 0.6 m, DE = 0.8 m, EF = 0.3 m and AF = 1.2 m.

The perimeter of a rhombus is 52 cm. If one diagonal is 24 cm; find:
(i) The length of its other diagonal,
(ii) Its area.
Find the diagonal of a quadrilateral whose area is 756cm2 and the perpendicular from the opposite vertices are 17cm and 19cm.
In the following, find the value of ‘a’ for which the given points are collinear
(2, 3), (4, a) and (6, – 3)
Find the area of the quadrilateral whose vertices are at (– 9, – 2), (– 8, – 4), (2, 2) and (1, – 3)
Let P(11, 7), Q(13.5, 4) and R(9.5, 4) be the midpoints of the sides AB, BC and AC respectively of ∆ABC. Find the coordinates of the vertices A, B and C. Hence find the area of ∆ABC and compare this with area of ∆PQR.
