Advertisements
Advertisements
प्रश्न
The perimeter of a rhombus is 52 cm. If one diagonal is 24 cm; find:
(i) The length of its other diagonal,
(ii) Its area.
Advertisements
उत्तर
Let a be the length of each side of the rhombus.
4a = perimeter
4a = 52
a = 13 cm
(i) It is given that,
AC= 24 cm
We have to find BD.
Now
`a^2 = ( "AC"/2 )^2 + ( "BD"/2)^2`
`13^2 = 12^2 + ("BD"/2)^2`
`( "BD"/2 )^2 = 5^2`
BD = 10 cm
Hence the other diagonal is 10cm.
(ii) Area of the rhombus = `1/2` x AC x BD
= `1/2` x 24 x 10
= 120 sq.cm.
APPEARS IN
संबंधित प्रश्न
The distance between parallel sides of a trapezium is 15 cm and the length of the line segment joining the mid-points of its non-parallel sides is 26 cm. Find the area of the trapezium.
The diagonals of a quadrilateral are 16 cm and 13 cm. If they intersect each other at right angles; find the area of the quadrilateral.
The area of a rectangular is 640 m2. Taking its length as x cm; find in terms of x, the width of the rectangle. If the perimeter of the rectangle is 104 m; find its dimensions.
Trapezium given below; find its area.
Trapezium given below; find its area.
How many tiles, each of area 400 cm2, will be needed to pave a footpath which is 2 m wide and surrounds a grass plot 25 m long and 13 m wide?
The length of a rectangular verandah is 3 m more than its breadth. The numerical value of its area is equal to the numerical value of its perimeter.
(i) Taking x as the breadth of the verandah, write an equation in x that represents the above statement
(ii) Solve the equation obtained in (i) above and hence find the dimensions of the verandah.
Using the information in the following figure, find its area.
A quadrilateral field of unequal has a longer diagonal with 140m. The perpendiculars from opposite vertives upon this diagonal are 20m and 14m. Find the area of the field.
When proving that a quadrilateral is a trapezium, it is necessary to show
