Question

ABCD is a square with each side 12 cm. P is a point on BC such that area of  ΔABP: area of trapezium APCD = 1: 5. Find the length of CP.

Answer 1

The figure is shown below:

`"Area of ΔABP"/"Area of trapezium APCD" = 1/5`

⇒ `[ 1/2 xx 12 xx ( 12 - "CP" )]/[ 1/2 xx ( 12 +"CP") xx 12] = 1/5`

⇒ 60 - 5CP = 12 + CP
⇒  6CP = 48
⇒ CP = 8 cm.