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Question
The following diagram shows a pentagonal field ABCDE in which the lengths of AF, FG, GH, and HD are 50 m, 40 m, 15 m and 25 m, respectively, and the lengths of perpendiculars BF, CH and EG are 50 m, 25 m and 60 m respectively. Determine the area of the field.
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Solution
We can divide the field into three triangles and one trapezium.
Let A, B, C be the three triangular regions and D be the trapezoidal region.
Now,
Area of A = `1/2` x AD x GE
= `1/2` x ( 50 + 40 + 15 + 25 ) x 60
= 3900 sq.m
Area of B = `1/2` x AF x BF
= `1/2` x 50 x 50
= 1250 sq.m
Area of C = `1/2` x HD x CH
= `1/2` x 25 x 25
= 312.5 sq.m.
Area of D = `1/2` x ( BF + CH ) x ( FG + GH )
= `1/2` x ( 50 + 25 ) x ( 40 + 15 )
= `1/2` x 75 x 55
= 2062.5 sq.cm
Area of the figure = Area of A + Area of B + Area of C + Area of D
= 3900 + 1250 + 312.5 + 2062.5
= 7525 sq.m
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