Advertisements
Advertisements
Question
Calculate the area of the figure given below:
Which is not drawn scale.
Advertisements
Solution
Here we found two geometrical figures,
One is a triangle and the other is a trapezium.
Now,
Area of the Triangle = `1/2 xx 12 xx 25`
= 150 sq. cm
Area of Trapezium = `1/2 xx ( 25 + 15 ) xx ( sqrt(26^2 - ( 25 - 15 )^2))`
= 20 × 24
= 480 sq. cm
Hence, the area of the whole figure = 150 + 480
= 630 sq. cm
APPEARS IN
RELATED QUESTIONS
The diagonals of a quadrilateral are 16 cm and 13 cm. If they intersect each other at right angles; find the area of the quadrilateral.
The area of a rectangular is 640 m2. Taking its length as x cm; find in terms of x, the width of the rectangle. If the perimeter of the rectangle is 104 m; find its dimensions.
Trapezium given below; find its area.
Two adjacent sides of a parallelogram are 24 cm and 18 cm. If the distance between the longer sides is 12 cm; find the distance between the shorter sides.
A floor that measures 15 m x 8 m is to be laid with tiles measuring 50 cm x 25 cm. Find the number of tiles required.
Further, if a carpet is laid on the floor so that a space of 1 m exists between its edges and the edges of the floor, what fraction of the floor is left uncovered?
Find the area and the perimeter of a square with diagonal 24 cm. [Take √2 = 1.41 ]
Find the diagonal of a quadrilateral whose area is 756cm2 and the perpendicular from the opposite vertices are 17cm and 19cm.
Vertices of given triangles are taken in order and their areas are provided aside. Find the value of ‘p’.
| Vertices | Area (sq.units) |
| (p, p), (5, 6), (5, –2) | 32 |
When proving that a quadrilateral is a parallelogram by using slopes you must find
If vertices of a quadrilateral are at A(– 5, 7), B(– 4, k), C(– 1, – 6) and D(4, 5) and its area is 72 sq. units. Find the value of k.
