Question

The figure given below shows the cross-section of a concrete structure. Calculate the area of cross-section if AB = 1.8 cm, CD = 0.6 m, DE = 0.8 m, EF = 0.3 m and AF = 1.2 m.

Answer 1

The diagram is redrawn as follows:

Here

AF = 1.2 m, EF = 0.3m, DC = 0.6m, BK = 1.8 - 0.6 - 0.3 = 0.9 m

Hence,

Area of ABCDEF = Area of AHEF + Area of HKCD + ΔKBC

= 1.2 × 0.3 + 2 × 0.6 + `1/2` × 2 × 0.9

= 0.36 + 2.1

= 2.46 sq.m