Question

Determine P(E|F).

Two coins are tossed once, where 

E: no tail appears, F: no head appears

Answer 1

S = {HH, TH, HT, TT}

n(S) = 4

E: no tail appears,

E = {HH}

n(E) = 1

P(E) = `(n(E))/(n(S)) = 1/4`

F: no head appears

F = {TT}

n(F) = 1

P(F) = `(n(F))/(n(S)) = 1/4`

E ∩ F = Φ, n(E ∩ F) = 0, P(E ∩ F) = 0

P(E | F) = `(P(E ∩ F))/(P(F))`

`= 0/(1/4)`

= 0