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Question
One bag contains 5 white and 3 black balls. Another bag contains 4 white and 6 black balls. If one ball is drawn from each bag, find the probability that both are black
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Solution
First Bag contains 5 white and 3 black balls
Total number of balls in the first bag 8 Second Bag contains 4 white and 6 black halls
Total number of balls in the second bag = 10
One ball is drawn from each bag.
P(getting both are black) = P(getting black ball from the first bag) × P(getting the ball from the second bag)
= `(""^3"C"_1)/(""^8"C"_1) xx (""^6"C"_1)/(""^10"C"_1)`
= `3/8 xx 6/10`
= `9/40`
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