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Question
One bag contains 5 white and 3 black balls. Another bag contains 4 white and 6 black balls. If one ball is drawn from each bag, find the probability that both are white
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Solution
First Bag contains 5 white and 3 black balls
Total number of balls in the first bag 8 Second Bag contains 4 white and 6 black halls
Total number of balls in the second bag = 10
One ball is drawn from each bag.
P(getting both are white) = P(getting white ball from the first bag) × P(getting the white ball from the second bag)
= `(""^5"C"_1)/(""^5"C"_1) xx (""^4"C"_1)/(""^10"C"_1)`
= `5/8 xx 4/10`
= `1/4`
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