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If P(A) = 0.8, P(B) = 0.5 and P(B|A) = 0.4, find i. P(A ∩ B) ii. P(A|B) iii. P(A ∪ B)

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Question

If P(A) = 0.8, P(B) = 0.5 and P(B|A) = 0.4, find

  1. P(A ∩ B)
  2. P(A|B)
  3. P(A ∪ B)
Sum
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Solution

(i) Given P(B|A) = 0.4

⇒ `(P (A cap B))/(P(A)) = 0.4`

⇒ P(A ∩ B) = P (A) × 0.4

= 0.8 × 0.4

= 0.32

(ii) `P(A|B) = (P (AcapB))/(P(B))`

`= 0.32/0.5`

= 0.64

(iii) P(A ∪ B) = P (A) + P (B) - P (A ∩ B)

= 0.8 + 0.5 - 0.32

= 1.3 - 0.32

= 0.98

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Chapter 13: Probability - Exercise 13.1 [Page 538]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 13 Probability
Exercise 13.1 | Q 3.1 | Page 538

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