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Question
Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.2, find P (E|F) and P(F|E).
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Solution
Given P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.2
`P(E|F) = (P(E ∩ F))/(P(E)) = 0.2/0.3 = 2/3`
and `P(F|E) = (P(E ∩ F))/(P(E)) = 0.2/0.6 = 1/3`
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