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Two cards are drawn one after the other from a pack of 52 cards without replacement. What is the probability that both the cards drawn are face cards?

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Question

Two cards are drawn one after the other from a pack of 52 cards without replacement. What is the probability that both the cards drawn are face cards?

Sum
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Solution

Let A ≡ the event that first card is a face card

B ≡ the event that second card is a face card

Since there are 12 face cards in the pack of 52 cards,

P(A) = `12/52 = 3/13`

`"P"("B"//"A")` = Probability that second card is a face card under the condition that first face card is not replaced. When the second card is drawn, the pack has 51 cards including 11 face cards.

∴ `"P"("B"//"A") = 11/51`

∴ the required probability = P(A ∩ B)

= `"P"("A")*"P"("B"//"A")`

= `3/13 xx 11/51`

= `11/221`.

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Chapter 9: Probability - Exercise 9.3 [Page 206]

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