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Question
Three cards are drawn at random (without replacement) from a well-shuffled pack of 52 playing cards. Find the probability distribution of the number of red cards. Hence, find the mean of the distribution.
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Solution
Let the random variable X= No. of red cards
Here, X can take values 0,1,2,3.
Now, P(X=0)=P(All black cards)=
\[P(B) \times P\left( BB|B \right) \times P\left( BBB|BB \right)\]
=\[\frac{26}{52} \times \frac{25}{51} \times \frac{24}{50} = \frac{2}{17}\]
P(X=1)= \[P(RBB) + P(BRB) + P(BBR)\]
\[= 3 \times P(R) \times P(B|R) \times P(B|RB) = 3 \times \frac{26}{52} \times \frac{26}{51} \times \frac{25}{50} = \frac{13}{34}\]
P(X=3)=P(All red cards)=
\[P(R) \times P(RR|R) \times P(RRR|R) = \frac{26}{52} \times \frac{25}{51} \times \frac{24}{50} = \frac{2}{17}\]
So, the probability distribution of X is as shown:
| x | 0 | 1 | 2 | 3 |
| P(x) | \[\frac{2}{17}\] | \[\frac{13}{34}\] | \[\frac{13}{34}\] | \[\frac{2}{17}\] |
\[\therefore \text { Mean }, E(X) = \sum x_i p_i = 0 \times \frac{2}{17} + 1 \times \frac{13}{34} + 2 \times \frac{13}{34} + 3 \times \frac{2}{17}\]
\[ = 1 . 5\]
