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Box I Contains Two White and Three Black Balls. Box Ii Contains Four White and One Black Balls and Box Iii Contains Three White ·And Four Black Balls. a Dice Having Three Red, Two Yellow and One Green Face, is Thrown to Select the Box. If Red Face Turns Up, We Pick up the Box I, If a Yellow Face Turns up We Pick up Box Ii, Otherwise, We Pick up Box Iii. Then, We Draw a Ball from the Selected Box. If the Ball is Drawn is White, What is the Probability that the Dice Had Turned up with a Red Face? - Mathematics

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Question

Box I contains two white and three black balls. Box II contains four white and one black balls and box III contains three white ·and four black balls. A dice having three red, two yellow and one green face, is thrown to select the box. If red face turns up, we pick up the box I, if a yellow face turns up we pick up box II, otherwise, we pick up box III. Then, we draw a ball from the selected box. If the ball is drawn is white, what is the probability that the dice had turned up with a red face?

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Solution

P(Total) = `1/2 xx 2/5  + 1/3 xx 4/5 + 1/6 xx 3/7`

`=1/5 + 4/15 + 1/14`

`= (42 + 56 + 15)/210`

`= 113/210`

`P(R"/"W) = (P(R).P(W"/"R))/"P(Total)"`

`= (1/2 xx 2/5)/(113/210)`

`= 1/5 xx 210/113`

`= 42/113`

 

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2014-2015 (March)

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