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Question
Calculate the amount of energy transferred by a 10 A electric current flowing through a resistor of 5 o for 15 minutes.
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Solution
As per Joule's law,
H=I2Rt
Here, I= 10 A, R = 5`Omega` and t=15 mins = 900s
H = (10)2 x 5 x (900) = 4.5 x 105 J
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